Comment #93
splitting-argument must not be first argument
| Status: | Open | Start: | 12/03/2009 | |
| Priority: | Low | Due date: | ||
| Assigned to: | - | % Done: | 0% |
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| Category: | - | |||
| Target version: | - | |||
| Clause: | 11.2.1 |
Page and Line: | 42:35 |
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Description
If the operator-expression-list of an argument-in-parentheses occurs, the first operator-expression of the operator-expression-list is called the first argument.
If a splatting-argument is the first argument, whitespaces shall not occur between its * and operator-expression.
A splitting-argument seems not to occur as "the first argument" because
"the first argument" is the first operator-expression and
operator-expression does not include splitting-argument.
Also, the following program is allowed in the current implementation:
def foo(x); end
foo(* [1])I may misunderstand the spec. What is the intention of that sentence in the
spec?
History
Updated by Yusuke Endoh 278 days ago
I understood. This sentence forbids whitespace when argument list has no
parentheses:
def foo(x); end
foo * [1]How about:
If the operator-expression-list of an argument-in-parentheses occurs, the first operator-expression of the operator-expression-list is called the first argument. If the indexing-argument-list has only one splatting-arguments, the splatting-arguments is also called the first argument.
Updated by Shugo Maeda 270 days ago
Yusuke Endoh wrote:
I understood. This sentence forbids whitespace when argument list has no parentheses:
def foo(x); end foo * [1]
How about:
If the operator-expression-list of an argument-in-parentheses occurs, the first operator-expression of the operator-expression-list is called the first argument. If the indexing-argument-list has only one splatting-arguments, the splatting-arguments is also called the first argument.
A block-argument can also be the first argument. So, how about the following?
If the operator-expression-list of an argument-in-parentheses occurs, the first operator-expression of the operator-expression-list is called the first argument.
If an argument-in-parentheses is of the form splatting-argument (, block-argument)?, then the splatting-argument is called the first argument, and whitespaces shall not occur between its * and operator-expression.
If an argument-in-parentheses is of the form block-argument, then the splatting-argument is called the first argument, and whitespaces shall not occur between its & and operator-expression.